Question

Simplify.
http://media01.owotw.com/g_alg01_2011/13/img_test_problem86.gif

Answer 1

answers
y/4
1/y-4
4/y-4

Answer 2

Flip the second fraction upside-down(Second fraction is [y^2/16] It should become [16/y^2])
After that you will cancel the terms. So...

(y/4)+1 * (16/y^2)-1

Now subtract the denominators/numerators to simplify the terms:Z

(4/y)

Answer 3

Flipping the bottom equation allows you to change it from division to multiplication. This allows you too multiple terms which is much easier than dividing them.

Answer 4

*The bottom expression.*

Answer 5

ok thanks

Answer 6

Did I make it clear?

Answer 7

ya

Answer 8

Would you mind if I gave you another example?

Answer 9

yes please

Answer 10

I'll make sure to go into detail.

Answer 11

ok

Answer 12

\[\huge{\frac{\frac{y}{4}+1}{\frac{y^2}{16}-1}}\]\[\huge{\frac{\frac{y}{4}+1}{(\frac{y}{4}-1)(\frac{y}{4}+1)}}\]

Answer 13

Rewrite it as the numerator times the reciprocal
of the denominator.

x^2 - 25
---------
8^8
-------------- = x^2 - 25 x^3
x - 5 --------- * --------- < --- Now we must factor:..:...
--------- x^8 x - 5
x^3

-----------------------------------------------------------------------

Upon factoring the trinomial we get:

= (x + 5)(x - 5) x^3
------------- * -------- <--- The (x - 5) both cancel out.
x^8 x - 5 <--- The powers subtract/cancel. 8-3 = 5
-----------------------------------------------------------------------
x + 5
After canceling we're left with: -------
x^5

Division -- which effectively this is -- becomes multiplication by the reciprocal.

Answer 14

so y/4+1 cancels and u are left with\[\huge{}\frac{1}{\frac{y}{4}-1}=\frac{4}{y-4}\]

Answer 15

thanks guys

Answer 16

use\[a^2-b^2=(a-b)(a+b)\]so in ur question\[\frac{y^2}{16}-1=(\frac{y}{4}-1)(\frac{y}{4}+1)\]