\[x(x^2 +y^2)^2(ydx - xdy) + y^6dy = 0\] anyone have any ideas?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (compassionate):
You want me too solve it?
OpenStudy (lgbasallote):
sure...if you can lol
OpenStudy (compassionate):
\[x(x^2 + y^2)^2 (0) = -dy^7\]
OpenStudy (anonymous):
divide it by y^6...it gets in to standard form
OpenStudy (lgbasallote):
0??/ o.O
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
hint : (ydx - xdy)/y^2 = d(x/y)
OpenStudy (lgbasallote):
idk if that made sense to me o.O
OpenStudy (anonymous):
cmon divide the entire thing by y^6
OpenStudy (anonymous):
(x/y)*(1+(x/y)^2))^2 * d(x/y) + dy = 0
OpenStudy (anonymous):
put x/y = t
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
wait...how did ydx - xdy)/y^2 = d(x/y) first?
OpenStudy (anonymous):
ok wat's d(x/y)
OpenStudy (lgbasallote):
dx/y?
OpenStudy (lgbasallote):
or do you mean derivative of 9x/y)?
OpenStudy (lgbasallote):
derivative of (x/y)*
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
d(x/y) yep derivative of x/y
OpenStudy (anonymous):
What's your question?
OpenStudy (lgbasallote):
the one in the blue box @beeqay
OpenStudy (lgbasallote):
@A.Avinash_Goutham with respect to what??
OpenStudy (anonymous):
I mean you have an equation fine, but what is the question, find dy/dx find dx/dy... solve for y.. Solve for x? Possibilities are a countless, so what's your question?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
uhh i thought all differential equations instruction is to find the solutioN?
OpenStudy (lgbasallote):
well anyway that's what's needed...a solution
OpenStudy (anonymous):
Ok, but still, you're question isn't specific enough, do you want dy/dx or dx/dy?
there's a difference
OpenStudy (lgbasallote):
trivial question....
OpenStudy (anonymous):
well it's a standard integrallll :P
um the solutiion is y a function of x :P
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
^whatever that meant haha
OpenStudy (anonymous):
????
OpenStudy (lgbasallote):
so back to the question pls?
OpenStudy (anonymous):
well the qn is solve :P
OpenStudy (lgbasallote):
how?/
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
t(1+t2)dt + dy = 0
OpenStudy (anonymous):
integrate that
OpenStudy (lgbasallote):
where did that come from?!!
OpenStudy (anonymous):
(1+t2)2 * sorry
OpenStudy (anonymous):
t = x/y
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
where did t come from =_=
OpenStudy (lgbasallote):
t = x/y so ?
OpenStudy (compassionate):
This thread is hilarious.
OpenStudy (lgbasallote):
indeed
OpenStudy (compassionate):
Do you still not understand?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
yeah
OpenStudy (compassionate):
Factor first.
OpenStudy (lgbasallote):
how is dt = ydx - xdy
OpenStudy (lgbasallote):
factor what?
OpenStudy (anonymous):
dt is that upon y2
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (compassionate):
Lol.
OpenStudy (compassionate):
This is thread of the year.
OpenStudy (lgbasallote):
lol why?
OpenStudy (compassionate):
Factor your squared equations to simplify some more before going through all the work.
OpenStudy (compassionate):
Lol. You're totally not getting it.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
factor?!
OpenStudy (lgbasallote):
im dyslexic :p lol
OpenStudy (compassionate):
Yes, Avin. You can factor in this particular one.
OpenStudy (compassionate):
I do it all the time. It makes it easier.
OpenStudy (lgbasallote):
i cannot see anything factorable o.O
Still Need Help?
Join the QuestionCove community and study together with friends!