Question

The sum of n from 1 to 99 for all n
1/ (n(n+1))

Answer 1

How do you find the sum of..

1/1.2+1/2.3+1/3.4.... +1/99.100 ????

plss help me..

Answer 2

try factorization

Answer 3

experimentX plss help me.. i dont know to how find the sum..

Answer 4

\[ \frac{1}{n(n+1)} = \frac{1}{n} - \frac{1}{n+1} \]Now use telescoping ...

Answer 5

Just try some first (my way) like
(1/1.2)+(1/2.3)=2/3 so it becomes denominator of last number making first numerator so ans is 99/100

Answer 6

what is the solution?

Answer 7

\[ \frac 11 - \frac12 + \frac 12 - \frac 13 +\frac 13 + ... + \frac 1{99} - \frac 1 {100} \]

Answer 8

99/100 is the solution

Answer 9

Thank you ajaykharabe and experimentX....

Answer 10

Thanks for helping me.. :)