A floor has two square-shaped designs. The area of the second square-shaped design is sixteen times greater than the area of the first square-shaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares?

Question

anonymous · Answer

if A and B are the areas of the two squares with A being the bigger square
And,
a^2 = A
b^2 = B
Then,
A = 16B
=> sqrt(A) = sqrt(16B)
a = 4b
Hope that answers your question!

anonymous · Answer

I think I got it.
Would the answer be, "The length of the side of the second square is 8 times greater than the length of the side of the first square."?

anonymous · Answer

Am! That would be 4 times, I think. That's why when we calculate the area (since we square the length of one side), 4 times 4 becomes 16.
to if 
length1 = 4*length2
that implies that:
area1 = 16*area2

anonymous · Answer

two floors consider a & b 
now b=16a
area of square = side square
so side b = sqrt b
and side a=sqrt 16a =4 sqrt a
so 4a =b