Find the perimeter of the trapezoid (see attached image)
help? :(
....
@Liz1911 Perimeter is the sum of all the sides, we have all the sides, Can you do it?
So it would be x over 16?
\[\frac x 4+\frac x 4+\frac x 4+\frac {2x} 4=??\]
2/16???
Liz what's \[\frac 1 5+\frac 1 5=?\]
2/10
I think you have a confusion \[\frac {1}{5}+\frac 1 5 =\frac 25\] Do you want me to explain how fractions work?
Um sure... I'm terrible at math lol..
OK, Suppose you have an apple, I break it into two , what are both parts in terms of the original apple?
1/2? ...
Good, if you have two add two fractions say \[\frac 2 4+ \frac 3 4\] First notice the denominators of both, if they are same, you can add the numerators!! here we get \[\frac 2 4+ \frac 3 4=\frac 5 4\] Tell me what's this? \[\frac {1}{2}+\frac {1}{2}\] ?
Ohhh. So if denominators are the same you don't add them?
We never add denominators whether they are same or not!!
Ohh sorry!
Don't be sorry, you have done nothing wrong. Did you get my point?
Yes:) So would it just be 2x/4 or 8x/4?
Add all of them \[ {\frac{x}{4}+\frac{x}{4}}+\frac{x}{4}+\frac{2x}{4}\] \[\underline {\frac{x}{4}+\frac{x}{4}}+\frac{x}{4}+\frac{2x}{4}\] \[\frac {2x} 4+\frac{x}{4}+\frac{2x}{4}\]Now you solve the rest?
4x/4 =1 ? Or 6x/4?
\[{\frac {2x} 4+\frac{x}{4}}+\frac{2x}{4}=\frac{2x+x+2x}{4}\] ??
Okay, I'm dumb, I don't get it how I'm wrong lol.
what's \[2+1+2=?\]
Oh...So the x is 1? lol (its 5 btw)
No x is not 1 , I just wanted to show that it'll be added like numbers \[2x+x+2x=5x\]
@Liz1911 I gotta go now, Sorry. My BFF @rebeccaskell94 will help you out
okay I'm not quite exactly sure where we're at so if you wanna give me the problem you have as it is now that would be helpful! oh and we assume x to be a 1 in an equation for simplicity's sake :)
I get it now, ash did a good job of explaining it to me lol. But thanks for helping. :)
oh, great!
Don't forget to give him a medal :)
@Liz1911 Do you understand?
Yes :)
@Liz1911 tell me what's \[\frac {4x} 6+\frac {x} 6\]
5x/6
\[\Huge \color {gold}{\text{Good work :)}}\]
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