Question

In how many ways can a committee of size 3 be formed from 5 people? Assume that, when people are chosen for a committee, the order of the choices does not matter.

Answer 1

using combinations:
\[choices = _{5}C_{3} = 10 ways\]

Answer 2

thanks is their a way to do in calculator?

Answer 3

no need
\[\frac{5\times 4}{2}=5\times 2=10\]

Answer 4

@CaseyC there is, depending on your calculator. What type do you have?

Answer 5

but yes, most calculators have this feature. depends on the calculator though

Answer 6

In general \[\binom n r =\frac{ n\times(n-1)\times(n-2)\times(n-3)\times\cdots \times(n-r+1)}{r!} \]

Answer 7

14,190?

Answer 8

14,190...wow

Answer 9

that is my kind of mistake!

Answer 10

@vic1 Casey C wants combinations, not permutations.