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(__)^2= (csc x-1)(csc x+1) solve for the blank
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would it be cscx^2
it would be \[\csc^{2} x\]
okay
(csc x-1)(csc x+1) = \[\csc^{2}(x) - 1 = (blank)^{2}\] so \[\sqrt{\csc2(x)−1} = blank\]
Nolastudent-- you're way makes sense, but is there a way to simplify is more?
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yes, sorry, trig identity: csc^2(x)-1 = cot^2(x)
*your*. Sorry... :)
so square root of cotangent squared, which is cotangent.
That's okay, we're in the math section XD
Okay, that makes more sense. I can never simplify mine enough... :)
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LOL, thanks for the help gandalfwiz!
So the final answer is cotx?
yep
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