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Plutonium-240 decays according to the function Q(t)=Q(subscripto)e^(-kt) where Q represents the quantity remaining after t years and k is the decay constant, 0.00011... How long will it take 27 grams of plutonium-240 to decay to 9 grams?
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A. 18,900 years B. 2,100 years C. 1.44 years D. 9,990 years
you have\[Q(t) 9====>Q _{0}= 27 =====>k = 0.00011\] then \[9 = 27 e^-0.00011t\] or \[\frac{1}{3} = e^{-0.00011t}\] take the base e log of both sides \[\ln(\frac{1}{3}) = -0.00011t\] \[t = \frac{\ln(\frac{1}{3})}{-0.00011}\] all you need to do is evaluate t
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