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HELP! The force of attraction between two magnets F Newtons is inversely proportional to the square of the distance, d between the magnets. When the magnets are certain distance, the force is 10 Newtons. What is the force when this distance is doubled? -Please show your working as well.
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\[F=k/d ^{2}\]
F=10 N, when distance is doubled, the distance squared is multiplied by 4 so the force would be 1/4. So the answer is F=10/4 Newtons or 2.5 Newtons
Think of it this way:\[\frac{1}{d^2}\longrightarrow \frac{1}{(2d)^2}=\frac{1}{4}\left(\frac{1}{d^2}\right)\], which is clearly one quarter of the original.
So I multiply the force 10N with 1/4 as well?
Exactly.
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Okay, thank you so much! :)
nice dude yakeyglee
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