Question

Factor completely.

x2 - x - 35

A. prime

B. (x - 35)(x + 1)

C. (x - 5)(x + 7)

D. (x + 5)(x - 7)

Answer 1

A. Prime

Answer 2

y?

Answer 3

Because B = x^2 -34x -35
C = x^2 +2x -35
D = x^2 - 2x -35
There is no way to factor that equation

Answer 4

okk(:

Answer 5

\(x^2-x-35\) has roots at \(x=\frac{1}{2}\left(1+\sqrt{141}\right)\) and \(x=\frac{1}{2}\left(1-\sqrt{141}\right)\). So this can be factored as:
\[\left(x-\frac{1}{2}\left(1+\sqrt{141}\right) \right)\left(x-\frac{1}{2}\left(1-\sqrt{141}\right) \right)\]
However, factorization is considered "prime" if the roots are not integers. Our roots are not integers. Thus, \(x^2-x-35\) is prime.

Answer 6

ans is prime..

Answer 7

A) prime