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Mathematics 10 Online
OpenStudy (anonymous):

Log problem...will be posted below

OpenStudy (anonymous):

\[\log_{5}n= 1/3 \log_{5}64 + 1/2 \log_{5}49 \]

OpenStudy (callisto):

\[\log_{5}n= \frac{1}{3} \log_{5}64 + \frac{1}{2} \log_{5}49\]\[\log_{5}n= \log_{5}64^{\frac{1}{3}} + \log_{5}49^\frac{1}{2}\]\[\log_{5}n= \log_{5}(4^3)^{\frac{1}{3}} + \log_{5}(7^2)^\frac{1}{2}\]\[\log_{5}n= \log_{5}4 + \log_{5}7\]\[\log_{5}n= \log_{5}4\times 7\]\[\log_{5}n= \log_{5}28\]\[n=...?\] Note: useful log properties used here: \[(i)\ logx^m = mlogx\]\[(ii)\ logx + logy = logxy\]

OpenStudy (anonymous):

and so 28 is the answer?

OpenStudy (callisto):

Yes, I think... If I haven't made any mistakes :|

OpenStudy (anonymous):

thank you!

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