Question

help! find the limit. lim x--->0 1/x+4-14/and all over/x

Answer 1

Is this the question?
\[\lim_{x \rightarrow 0} \frac{\frac{1}{x+4}-14}{x}\]

Answer 2

yes but its -1/4 sorry :(

Answer 3

\[\lim_{x \rightarrow 0} \frac{\frac{1}{x+4}-\frac{1}{4}}{x}\]This?

Answer 4

yes :)

Answer 5

\[\lim_{x \rightarrow 0} \frac{\frac{1}{x+4}-\frac{1}{4}}{x}\]\[=\lim_{x \rightarrow 0} \frac{\frac{(4)}{4(x+4)}-\frac{(x+4)}{4(x+4)}}{x}\]\[=\lim_{x \rightarrow 0} \frac{\frac{4-(x+4)}{4(x+4)}}{x}\]\[=\lim_{x \rightarrow 0} \frac{-x}{4x(x+4)}\]\[=\lim_{x \rightarrow 0} \frac{-1}{4(x+4)}\]Can you continue from here? Just put x=0 into the fraction..

Answer 6

ok ummm yeah but will this give me -0.06?

Answer 7

okay i have two more questions...do u mind?

Answer 8

if i ask u 4 help?

Answer 9

It should be -1/16 .. :S
Sorry.. I have something to do now... I'll be back later..

Answer 10

okay thanks! :)

Answer 11

\[=\lim_{x \rightarrow 0} \frac{-1}{4(x+4)}\]\[= \frac{-1}{4(0+4)} \]\[= \frac{-1}{4(4)}\]\[= \frac{-1}{16}\]

Answer 12

thank u! :)))