List the possible rational rootsof P(x) given by the Rational Root Theorem.

Question

anonymous · Answer

$$P(x)=x^3+4^2+10x+6$$

shubhamsrg · Answer

well it'd be +/- (factors of coefficient of x^0 / factors of coefficient of highest power of x)
hence here its is +/- (factors of 6 / factors of 1)
+/- (1,2,3,6)/(1) 
any of all permutations and combinations of numerator and denominator can be a root

shubhamsrg · Answer

ohh..is it  4^2 or something else?

anonymous · Answer

yep its 4^2
Thank you very much though, this helped me!

shubhamsrg · Answer

well..for 4^2 ,,the constant term is not 6 but is 6+4^2 i.e. 22
so ans will be +/- (1,2,11,22)/(1)
sorry for above..

anonymous · Answer

Hmm, that's weird because I checked the book I'm doing this from and you were apparently correct the first time. 

Answer:$$\pm1,\pm2,\pm3,\pm6$$

shubhamsrg · Answer

in that case that should be 4^2 ..please re-check..could be x^2 or 4x^2 etc..

shubhamsrg · Answer

i mean that shouldn't be 4^2 **

anonymous · Answer

Oh i'm sorry you're right. I misread the first time you asked me what it was. I checked it again and it's 4x^2. Thank you!

shubhamsrg · Answer

glad to help ^_^