Question

A chemist collects 156 mL of N2 gas at 25ºC and 7.9 x 10^2 torr. The volume of the gas at STP would be what?

Answer 1

pV=nRT --> n= pV/RT and then that n you put in:
n=V/Vm --> V= n*Vm

Answer 2

What is Vm?

Answer 3

molar volume -> 22,4 dm3 mol-1

Answer 4

Why do you subtract 1?

Answer 5

mol^-1

Answer 6

For some reason I'm not coming out with any answer that makes sense to the problem.

Answer 7

did you transfer pressure to Pa and temperature to K

Answer 8

and volume to m3

Answer 9

Yes. This is my equation.

V2 = (1.039 atm * 156 mL * 298.15 K)/(273.15 K * 1 atm)

Answer 10

???
n= pV/RT = 7,9*10^2 torr * 133,322 Pa torr-1 * 156 *10-6 m3 / 8,314 J K-1 mol-1 * 298 K = 6,63 *10^-3 mol
V= n * Vm= 6,63*10^-3 mol * 22,4 dm3 mol-1 = 0,148 dm3 = 148 cm3 or 148 mL

Answer 11

Ah... I was using the wrong gas law. Thank you for correcting me.

Answer 12

not a problem