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The order of a chemical reaction with respect to reactant A is zero. If you double [A], the rate a) remains the same b) doubles c) decreases by half d) quadruples
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\[-\frac{\text d[A]}{\text dt}=k[A]^0\] \[-\frac{\text d[A]}{\text dt}=k\]
So the answer would be B. A would be doubled.
how did you get that
Wait no
It would stay the same
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\[-\frac{\text d[A]}{\text dt}=k\] double \([A]\) \[-\frac{\text d[A]}{\text dt}=k\] the rate is still \(k\)
since A is zero it would stay the same. [A]^0
i think you mean \[[A]^0=[2A]^0=1\]
Yeah, accidentally submitted it without finishing it
Thank you
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