Question

What is the equation for the base ionization constant of PO4^(3-)?

Answer 1

Ka or Kb = [H+] [X-] / [HX]

Answer 2

in case of Kb it is [OH-] [Y] / [YOH]

Answer 3

and google found this so read:
http://library.thinkquest.org/C006669/data/Chem/equilibrium/kb.html

Answer 4

and:
http://library.thinkquest.org/C006669/data/Chem/equilibrium/ka.html

Answer 5

It's Kb

Answer 6

Could it possibly be [HPO4(2-)][OH(-)]/[PO4(3-)]?

Answer 7

you said PO4 3- and it is acid ad when you calculate Ka then you get Kb by: Ka+Kb=Kw
Ka= [PO4 3-][H+]/[HPO42-]

Answer 8

a) Kb = [HPO4(2-)][OH(-)]/[PO4(3-)]
b) Kb = [HPO4(2-)][OH(-)/[PO4(3-)][H2O]
c) Kb = [PO4(3-)]/[HPO4(2-)][OH(-)]
d) Kb = [HPO4(3)][OH(-)]/[PO4(3-)]

Answer 9

oh, ok in this case it is:
a) Kb = [HPO4(2-)][OH(-)]/[PO4(3-)]