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OpenStudy (anonymous):
A substance of unknown mass absorbs 1932 joules of energy, going from 26 to 42 degrees Celsius. If the specific heat of the substance is 4.29 J/g·°C, how much of the substance is present?
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OpenStudy (anonymous):
DH= m cp DT = 4,29 J/gC * 16 °C = 68,64 *m = 1932 J -> m= 1932 J /68,64 J/g = 28,14 g
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