Multiply sqrt[3]{9x^5}*sqrt[3]{24x}
Simplify the product

Question

Multiply sqrt[3]{9x^5}*sqrt[3]{24x}
Simplify the product

anonymous · Answer

$$\sqrt[3]{9x^5}*\sqrt[3]{24x}$$

parthkohli · Answer

$ \color{Black}{\Rightarrow \sqrt[3]{x} \times \sqrt[3]{y} = \sqrt[3]{xy} }$

Multiply both and put it under the radical.

parthkohli · Answer

$ \color{Black}{\Rightarrow \large \sqrt[3]{9x^5 \times 24x}  }$

lgbasallote · Answer

you have same indeces sp it's just $$\sqrt[3]{(9x^5) \times (24x)}$$

inkyvoyd · Answer

btw, for texing, put it in
\(

inkyvoyd · Answer

and \)

lgbasallote · Answer

so it's equal to $$\sqrt[3]{216x^6}$$ got it?

lgbasallote · Answer

i just multiplied 9x^5 and 24x

parthkohli · Answer

It can be simplified.

$ \color{Black}{\Rightarrow 6x^2}$

lgbasallote · Answer

216 and x^6 are perfect cubes (i believe)

inkyvoyd · Answer

Guys, it is a very bad idea to do that.

parthkohli · Answer

$ \color{Black}{\Rightarrow \sqrt[3]{216} \times \sqrt[3]{x^6} = 6 \times x^2 = 6x^2 }$

anonymous · Answer

Why is it a bad idea?

lgbasallote · Answer

coz he's a troll...the blank pic is a giveaway isnt it ;D

anonymous · Answer

@lgbasallote  haven't i seen you somewhere before?

parthkohli · Answer

lol he's a troll he put myin's pic

inkyvoyd · Answer

$\sqrt[3]{9x^5}*\sqrt[3]{24x}$
=$\sqrt[3]{x^5*x}*\sqrt[3]{24*9}$
=$\sqrt[3]{x^5*x}*\sqrt[3]{2^2*3*3^2}$
=$\sqrt[3]{x^5*x}*\sqrt[3]{2^2*3^3}$
=$\sqrt[3]{x^5*x}*2*3$
=$6\sqrt[3]{x^5*x}$
=$6\sqrt[3]{x^6}$
=$6x^2$

lgbasallote · Answer

hmm no @satellite73 i don't believe we've met

inkyvoyd · Answer

Never multiply something that you will factor. You are wasting time by multipling it and still having to factor it. it is ALWAYS a better idea to factor something, so taking radicals of it is easier.

inkyvoyd · Answer

@cubanito305

anonymous · Answer

is there a tutoral i can see on factoring, i always have trouble with that >.<

inkyvoyd · Answer

Well, I usually check if itis divisible by 2 or 3.
Remember, if the sum of the digits is a multiple of 3, it is divisible by 3. If it is even, it is divisible by 2.

lgbasallote · Answer

my factoring tutorial is on qadratic expressions

inkyvoyd · Answer

if it ends with a 5 or 0, it is divisible by 5. Divisbility by 7 is checkable too, but I usually do the whole long division.

inkyvoyd · Answer

factor any number out of the expression if possible, even if you know that you can't simplify it.

anonymous · Answer

thanks