Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(–2, – 16), and x intercepts at x = –6 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 4x − ___
Help me on this one it's hard

Answer 1

well the answer is y=x^2+4x+12

Answer 2

Well.
First of all,
Vertex is (-b/2a, -D/4a)
Let the constant be some C.
Then on satisfying -2 in the equation,

=> y = -2*-2 + -2*4 + c
We know that at this point y = -16.
=> -16 = 4 - 8 + c = > c = -12

Answer 3

Rest of the information is simply for you to confirm your answer.
Which is c = 12
Equation being, x^2 + 4x - 12.

Answer 4

cuz we have given the vertex ie (-2,-16) wichich is also equal to

(-b/2a, 4ac-b^2/4a) and by comparing the equation with ax^2+bx+c we'll get the answer

Answer 5

well there won't be '-" sign cause there is already one siddhantsharan

Answer 6

Yeah. But I assumed the equation as ax^2 + bx +c.
So I get c = -12.
=> Equation has a The constant term as -12.
Though as I specified above too, c = 12. ONLY because - sign is provided.
Your equation in the first post is incorrect. Check, it doesnt satisfy the roots.

Answer 7

well i guess you were right siddhantsharan