Question

write an equation in slope-intercept form for the line that satisfies the following condition. passes through (12,-4), perpendicular to the graph of y = 7/12x + 22

Answer 1

slope intercept form is y=mx + b, where m is the slope and b is the y intercept. Solve for the slope and the y intercept. Do know what is the relation between to perpendicular lines' slopes?

Answer 2

no..

Answer 3

Say we have a line A with slope Q. A line perpendicular to A has a slope of -1/Q (the negative reciprocal). So you know that the line y = 7/12x + 22 is perpendicular to the line you are solving for, so what does that tell you about the slope of the line you are solving for?

Answer 4

idk

Answer 5

Two lines that are perpendicular have slopes that are negative reciprocals of each other, so if you know the line you are looking for is perpendicular to y = 7/12x + 22, what is the slope of the line you are looking for?

Answer 6

idk im in 10 grade for summer school

Answer 7

The slope of the perpendicular line is 7/12, right? So what is the slope of the line you are looking for if it is perpendicular to line with a slope of 7/12, using the special relation I told you above.

Answer 8

i dont get it ill jsut fail.

Answer 9

I can't straight up tell you the answer; you won't learn anything that way. Why don't you ask your teacher to explain it to you? I am sure he/she will be more that willing to help you and won't fail you.

Answer 10

we dont have a teacher is summer school we are jsut on the computer all day.

Answer 11

This is the answer you can see the inverse and negate that nolastudent was talking about. now use the point given to find the constant of the second line


\[y=7/12x+22\]
\[y=\frac{-12}{7}x-\frac{140}{7}\]

Answer 12

using \[y=mx+c\] \[-4=\frac{-12 \times 12 } {7} x+c\]
\[-4=\frac{-144}{7}+c\]\[0=\frac{-140}{7}+c \] so \[c=\frac{140}{7}\] put that back into the equation to get
\[y=\frac{-12}{7}x - \frac{140}{7}\]\[y=\] hope this helps