Question

(2x2 – 23x + 63) ÷ (x – 7)
steps please, last one

Answer 1

bet this one factor too right?

Answer 2

and you can also guess that one of the factors is \(x-7\) so start with
\[2x^2-23x+63=(x-7)(\text{something})\] and see if we can figure out the "something"

Answer 3

first term of "something" must be \(2x\) because \(2x\times x=2x^2\) and last term must be \(-9\) because \(-9\times -7=63\) so you know it is
\[2x^2-23x+63=(x-7)(2x-9)\]

Answer 4

then as before you get
\[\frac{2x^2-23x+63}{x-7}=\frac{(x-7)(2x-9)}{x-7}\] cancel to finish