Jake has two similar cylindrical pipes. The radius of the first cylindrical pipe is 5 cm. The circumference of the second cylindrical pipe is 20π cm. The volume of the second cylindrical pipe is how many times greater than the volume of the first cylindrical pipe? 3 4 5 8
Do you know what the radius of the second pipe is?
You should be able to work it out
20pi = 2pir r = 10 V = pi r r= 25pi V = pi r r = 100pi
Can you work it out Blahh23?
I don't have the radius of the second pipe.. I cant figure it out:(
You are given the circumference of the second pipe
use the circumference equation C = 2pi*r
i tried already... the happy helper.. How do we found the radius from the circumference i know there is a way i forgot though.
HappyHelper has given you the formula for the circumference - use that to work out the radius of the second pipe
Oh i see. so the radius is 10 like her said up there.
yes - so now you know the radius has been doubled
yes.. so that means that the thing must be 4 times larger??
for similar solids, if there linear dimension is increased by a factor of r, then it means their volume is increased by a factor of \(r^3\)
but what is the height. we need that to find the volume ... ^ and idk what that means up there.....
in your case, the linear dimension (in this case the radius) was increased by a factor of 2. So the volume increases by a factor of \(2^3\)
if two solids are 'similar' - it means all their linear dimensions are in the same ratio
so if the radius has increased by a factor of 2, it means the height is also increased by a factor of 2
Oh okay........ so i should pick 2 as my answer correct?
no
do you know the formula for the volume of a cylinder in terms of its radius and height?
I am not here for medals.
TO answer your question up there. yes its v=ttr^2h
Join our real-time social learning platform and learn together with your friends!