guys can anyone help me with this http://picpaste.com/Capture-M96V1ESE.PNG

Question

anonymous · Answer

B

anonymous · Answer

just look at the y intercept of the graph when x=0... this is an exponential function of the form y=Ce^x

anonymous · Answer

thanks :)

anonymous · Answer

yw...:

campbell_st · Answer

look at each graph to find the y intercept by letting x = 0 and using the power of zero law

$$a^0= 1$$

$$A  y = 40^{50x}$$ 

let x = 0 you have $$y = 40^{50 \times 0} =======> y = 40^0 ==== y = 1$$

$$B y =  40e^x ======y = 40e^0 ===> y = 40 \times1 ====y = 40$$

$$C y = e^{40 \times 0} ==== y = e^0 =====y = 1$$

$$D y = 40^0===========> y = 1$$

anonymous · Answer

whbu this one http://tinypic.com/view.php?pic=15p05kw&s=6

campbell_st · Answer

find the value of 

$$e^1 = $$

then evaluate each of the possible answers to get a match

anonymous · Answer

so u don't know the answer lol

anonymous · Answer

i already found it is 2.048

campbell_st · Answer

well 

$$e^1 \approx 2.71828$$

so which of you possible answers is close to that

anonymous · Answer

not sure seriously is like c or d

campbell_st · Answer

well given its an exponetial problem I'd say the highest power

(1 + 1/14)^14

anonymous · Answer

is c  i guess right