Question

What is the equation of the line that passes through the point (4, 1) and is perpendicular to the line y = –2x + 4?

Answer 1

Do you know point-slope form of the equation of a line?

Answer 2

no i dont know any algebra im trying to help my sister finish her assignments. shes in the hospital. i dont need anyone to teach me anything i just dont want her to fail. any good answers anyone has is greatly appreciated

Answer 3

Sorry. It is contrary to the code of conduct to just post answers. Too many kids try to avoid learning that way.

Answer 4

could u show me how to work it out then? dont want anyone to get in trouble.

Answer 5

\[y-y _{1}=m(x-x _{1})\]

Answer 6

First, determine the slope of the given line.
x + 2y = 6
Solve for y to get this in slope-intercept form. Remember to switch signs when you switch sides.
2y = -x + 6
Divide all terms on both sides by 2.
y = -0.5 x + 3
So the slope of the given line is the coefficient of x, which is -0.5 = -1/2
The slope of a perpendicular line is the negative reciprocal of that slope, which would be 2.
Use the point-slope form to build the equation with the point (4,2)
y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.
y - 2 = 2(x - 4)
This is an equation that satisfies the question. To get this into slope-intercept form, expand, simplify and solve for y.
y = 2x - 8 + 2
y = 2x - 6

Answer 7

That is point-slope form.
The given line has slope -2 so the perpendicular has slope 1/2
replace y1with 1, m with 1/2 and x1 with 4 and simplify. That will be the equation of the desired line.

Answer 8

Yep, take it with a little grain of salt

Answer 9

so what do i have to simplify exactly?