Question

Help please :)

Answer 1

1. multiply the first equation by 15
2. then multiply the second equation by 9
3. then add the two equations and you should find that the 'y' terms cancel out so you should be able to solve for x
4. once you have found x, substitute its values into either one of the equations to solve for y

Answer 2

just 15 and just 9 ? no 1/15 or anything? And doesnt x=1 and y=1 in fraction? like x/5= 1/5? @asnaseer

Answer 3

the two equations given are:\[\frac{x}{5}-\frac{y}{15}=4\]\[\frac{x}{3}+\frac{y}{9}=1\]

Answer 4

if we multiply the first one by 15 we get:\[3x-y=60\]agreed?

Answer 5

so x and y are not one

Answer 6

x and y are unknown values at this point

Answer 7

x/5= 15x5?

Answer 8

no:\[15(\frac{x}{5}-\frac{y}{15})=15\times4\]therefore:\[15\times\frac{x}{5}-15\times\frac{y}{15}=60\]

Answer 9

the 5 below the x now cancels with the 15 next to it leaving 3
and the 15 below the y cancels with the 15 next to it

Answer 10

ok, now i see

Answer 11

now do the same with the second equation except this time multiply both sides by 9 - what do you get?

Answer 12

3x+1y=9

Answer 13

perfect! you can remove the '1' next to 'y' because '1y' is the same as 'y'

Answer 14

so now you are left with two simpler equations:\[3x-y=60\]\[3x+y=9\]

Answer 15

now add these two equations and what do you get?

Answer 16

ok, now i can use substitution to solve?

Answer 17

6x=69

Answer 18

x=11.5

Answer 19

perfect again :)

now substitute this value of x into one of the equations to get y

Answer 20

-25.5?

Answer 21

not negative. sorry

Answer 22

wait yes it is lol.

Answer 23

i did 3(11.5)-y=60

Answer 24

lets use this one:\[3x+y=9\]and you found:\[x=11.5\]therefore:\[y=9-3x=9-3*11.5=9-34.5=-25.5\]you are right again!

Answer 25

Aw yes! I entered on my homework and it correct. Thank you. The fractions are the only part that tricked me. Thanks so much :* :)

Answer 26

yw - I'm glad I was able to help you out :)

Answer 27

me too! :)

Answer 28

thx :)

Answer 29

np :)