what is the sum of 3/2x and 4/3x expressed in simplest form?
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jimthompson5910 (jim_thompson5910):
is 3/2x really \[\Large \frac{3}{2}x\] or is it \[\Large \frac{3}{2x}\] ???
OpenStudy (anonymous):
it is 3 over 2x the 2nd choice
jimthompson5910 (jim_thompson5910):
thanks
jimthompson5910 (jim_thompson5910):
In order to add these fractions, we need the denominators to be the same
jimthompson5910 (jim_thompson5910):
So how do we do that?
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jimthompson5910 (jim_thompson5910):
Any ideas?
OpenStudy (anonymous):
is the answer 7/5x
jimthompson5910 (jim_thompson5910):
not quite, you cannot just add the denominators
OpenStudy (anonymous):
o then i dont know what to do
jimthompson5910 (jim_thompson5910):
alright
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jimthompson5910 (jim_thompson5910):
We need the fractions to have the same and equal denominators.
jimthompson5910 (jim_thompson5910):
So we must get each denominator equal to the LCD
OpenStudy (anonymous):
the lcd of both numbers
jimthompson5910 (jim_thompson5910):
The denominators are 2x and 3x. So the LCD is 6x
So multiply the first fraction by 3/3 to get
\[\Large \frac{3*3}{3*2x} = \frac{9}{6x}\]
and multiply the second fraction by 2/2 to get
\[\Large \frac{2*4}{2*3x} = \frac{8}{6x}\]
OpenStudy (anonymous):
thank you i know what to do from here
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jimthompson5910 (jim_thompson5910):
So
\[\Large \frac{3}{2x}+\frac{4}{3x}\]
becomes
\[\Large \frac{9}{6x}+\frac{8}{6x}\]
and then you can add the numerators and place that over the LCD
jimthompson5910 (jim_thompson5910):
You're welcome. Let me know what you get for your answer.
OpenStudy (anonymous):
17/6x is that correct
jimthompson5910 (jim_thompson5910):
you nailed it, very nice
OpenStudy (anonymous):
thank you for helping
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