Question

This question is really throwing me off.
Michael throws a rock on Planet X at an angle of 59.4◦ with a speed of 30.2 m/s. It
reaches a maximum height of 215 m before falling back down to the ground.

(a) What is the acceleration due to gravity on Planet X, gX? Write your answer
first in units of m/s2 and then in units of g.
(b) How far along the x-direction does the rock travel?

Answer 1

Please show your work! I'd like to understand how to do it too. Thanks :)

Answer 2

for part (a)
do you know a formula including height, initial and final velocities, and acceleration \((-g_X)\)

Answer 3

?

Answer 4

\[\Delta x = v _{ox} \Delta t\] \[\Delta y=v _{oy} \Delta t + 1/2 a _{y} \Delta t ^{2}\]

I have those, but then I'd be missing Delta t, a in y direction and delta x.

Answer 5

something like
\[\Large {v}^2={v_0}^2+2a(\Delta x)\]

Answer 6

This can be used for projectile motion?

Answer 7

sorry it won't be Δx.... why not?
\[\Large v^2={v_0}^2+2as \]

Answer 8

Sorry, what does the s stand for?

Answer 9

s= displacement ...
velocites, acceleration, height are all the y components only

s=Δy = height

Answer 10

Alright, thank you! I'll try that out. My prof gave us two equations to use for projectile motion; the ones I stated above. Fingers crossed this works.

Answer 11

\[\Large v=0m/s\]
\[\Large v_0=30.2\times\sin\left(59.4\deg\right)m/s\]
\[\Large s=215m\]
\[\Large a=-g_X\]

Answer 12

Why is V not 30.2 m/s?

Answer 13

you can switch v and v_0 around, but then \(\Delta y = -215m\)