Question

What is the y intercept of the line that is parallel to 2x+3y=4 and contains the point (6,-2)?

Answer 1

parallel line has slope \(-\frac{2}{3}\) use the point slope formula to find the equation of your line and the y-intercept

Answer 2

\[y+2=-\frac{2}{3}(x-6)\] is a start,
formula is \(y-y_1=m(x-x_1)\)

Answer 3

2x+3y=4
3y=-2x+4
y=(-2/3)x+4
your line's slope is -2/3, so the perpendicular line is gonna have slope 3/2 (negative reciprocal)
so you have y=(3/2)x+b for your second line, so plug in the point
-2=(3/2)6+b
-2=9+b
b=-11
your y intercept is -11.

Answer 4

thats not one of the choices

Answer 5

you sure you typed the problem in correct? you're looking for a y intercept right, not an x? and the point is (6,-2) and the equation is right?

Answer 6

yea i did

Answer 7

it can be -2 1 2 3

Answer 8

ohhh sh*t. sorry. you said parallel, not perpendicular.
i looked at the first guy's answer and we both read your problem wrong.
so the first equation has slope -2/3, so your second equation will have slope -2/3 too.
y=(-2/3)x+b
-2=(-2/3)6+b
-2=-4+b
b=2

2 is your answer, sorry for that.

Answer 9

i am pretty sure that is what i said

Answer 10

\[y+2=-\frac{2}{3}(x-6)\]
\[y+2=-\frac{2}{3}x+4\]
\[y=-\frac{2}{3}x+2\]