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Mathematics 7 Online
OpenStudy (anonymous):

Let P(x) = F(x)G(x) and Q(x) = F(x)/G(x), where F and G are the functions whose graphs are shown. http://www.webassign.net/scalcet7/3-2-050.gif (a) Find P '(2). (b) Find Q'(7).

OpenStudy (anonymous):

webassign?

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

\[(fg)'=f'g+g'f\] so we need 4 numbers do to this: \[f(2),f'(2),g(2),g'(2)\]

OpenStudy (anonymous):

For that one the answer is 3/2. I can't figure part b out

OpenStudy (anonymous):

we have to read these off of the graph \(f(2)=3\) that is easy over 2, up 3 \(f'(2)=0\) because the tangent line is horizontal there

OpenStudy (anonymous):

p'(2)=F(2)G'(2)+F'(2)G(2) (product rule) so thatd be, 3*(1/2)+0(2) P'(2)=3/2

OpenStudy (anonymous):

\(g(2)=2\) again from the graph and \(g'(2)=\frac{2}{3}\)

OpenStudy (anonymous):

no that is wrong \(g'(2)=\frac{1}{2}\)

OpenStudy (anonymous):

plug in to the formula \[(\frac{f}{g})'=\frac{gf'-fg'}{g^2}\] to get the answer

OpenStudy (anonymous):

it is arithmetic from here on in

OpenStudy (anonymous):

I just can't find f'(7) or g'(7)

OpenStudy (anonymous):

oooh ok

OpenStudy (anonymous):

Q'(7)=[G(7)F'(7)-F(7)G'(7)]/G'(7)^2 (quotient rule, if you can read all that) so you have 1*(1/4)-5*(-2/3)/(-2/3)^2 so, 1/4-(-10/3)/(4/9) I'm sure you know how to do the algebra from there, the answer should be 387/48 or 8.0625

OpenStudy (anonymous):

\[g'(7)=-\frac{2}{3}\] from the picture

OpenStudy (anonymous):

try and follow what i wrote, i did that all out for you haha

OpenStudy (anonymous):

graph is a line, so slope is a constant the constant is the slope of the line, which you read off from your eyeballs. over 3, down 2, slope is \(-\frac{2}{3}\)

OpenStudy (anonymous):

similarly \(f'(7)=\frac{1}{4}\) since the line goes over 4 units, and up 1 unit

OpenStudy (anonymous):

is that part ok? because it is arithmetic from there on

OpenStudy (anonymous):

use my arithmetic haha

OpenStudy (anonymous):

The answer is either 10/12 , 55/12 , or 43/12

OpenStudy (anonymous):

no... first answer is 3/2, second answer is 387/48

OpenStudy (anonymous):

No it's multiple choice. it has to be one of the three

OpenStudy (anonymous):

we have \(f(7)=5,f'(7)=\frac{1}{4}, g(7)=1, g'(7)=-\frac{2}{3}\) yes?

OpenStudy (anonymous):

lets see \[\frac{1\times \frac{1}{4}+5\times \frac{2}{3}}{1^2}=\frac{1}{4}+\frac{10}{3}=\frac{43}{12}\]

OpenStudy (anonymous):

looks like we have a winner!

OpenStudy (anonymous):

Woot Woot!!!! Thank you!

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