Question

Help?




A parallelogram whose vertices have coordinates R(1, -1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ .

sqrt of ____

Answer 1

we need a picture

Answer 2

looks like short diagonal is one between the points (3,3) and (6,1)
http://www.wolframalpha.com/input/?i=plot+ {%281%2C+-1%29%2C+%286%2C+1%29%2C+%288%2C+5%29%2C++%283%2C+3%29}+

Answer 3

use the distance formula to find the distance
\[\sqrt{(6-3)^2+(3-1)^2}=\sqrt{3^2+2^2}=\sqrt{9+4}=\sqrt{13}\]

Answer 4

thank you thank you!