Question

I've been stuck on this problem for the an hour and a half... please help.
Find the solution to the equation log16^32 = x + 5. Using complete sentences, explain the procedure used to solve this equation.

Answer 1

log16/log32 = x + 5

Answer 2

How'd you get that? :O

Answer 3

Formula logb^U = logb/logU
from Pre-Calc

Answer 4

Well this is algebra 2 so they haven't taught us that :/
They only gave us this formula:
y = b^x x = logb y

Answer 5

\[\log_{16}{32} = x + 5\]\[\frac{\log_232}{\log_216}=x+5\]\[\frac{\log_22^5}{\log_22^4}=x+5\]\[\frac{5\log_22}{4\log_22}=x+5\]\[\frac{5}{4}=x+5\]\[\cdots=x\]

Answer 6

then it should be
16^(x+5) = 32 because ( log16^32 = x+5) use the x=logb y => y=b^x
2^4(x+5)= 2^5
4(x+5) = 5 ( omit 2 because they have the same base)
4x + 20 = 5
4x = -15
x = -15/4

Answer 7

Ohh,
sorry it's hard learning off of a virtual teacher.
Thank you, i think i get it now