which of the following is the equation of a line that passes through (-2,-1) and (-4,-3)? y=1/2x + 1, y=x + 1, y =1/2x - 1, or y = x - 1
Hello, lets first look at what the slop must be. We know to have a slope, we must have at least 2 points, and they must lie on a straight line. Lets call these two points P1, and P2.
The formula for slope is \[m = \frac{y2-y1}{x2-x1}\]
So in this case, point P1 has coordinates (x1,y1) = (-2,-1) and point P2 has coordinates (x2,y2)=(-4,-3)
Plugging those into the slope you get (-3-(-1))/(-4-(-2)) = m = 1
so it is either choice b or choice d
to find out which, we must use the point-slope form of the line \[m = (y-y1)/(x-x1) or y = m(x-x1) + y1\]
oooh my!
yeah that came out like crap
its y=m(x-x1) + y1
now we have m, y1, and x1
what's m?
the slope
which is 1 in this case, using the two points we are given
ugh im just trying to prepare for this Pert test! trying to make sure i understand EVERYTHING
ahh, answer should be y =x -1
Show me why
So we have 2 points, (-2,-1) and (-4,-3), do you know how to find slope given 2 points?
I think so.. I kind of remember that
so if you graph the two points, and connect a line its (rise)/(run) so how far do i have to go in the y direction divided by how far i have to go in the x direction between the two points
in the y direction I go from (-3 to -1) total distance
and in the x direction i go from -4 to -2
or sorry, i had that backwards in the y direction we go from -1 to -3 and from -2 to -4 in x
:(
lol, ok let me graph something real quick
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