Can someone walk me through how to make a trinomial a perfect square?
via completing the square method...give me a trinomial
The first one is x²+10x+c and we have to find the value of c
divide 10 by 2 what do you have?
add square of half the coefficient of x&y referance sweart calculus sixth edition.
When you divide 10 by 2 you get 5.
now square that
what is \(5^2\)?
25
therefore, for x^2 + 10x + c to become a perfect square trinomial...c must be 25
because x^2 + 10x + 25 = (x+5)^2 got it?
I'm sorry.. I'm a really slow learner holy wow. Can we do a few until I get the hang of it? :)
sure
Thanks! :) Number 2 is x²-8x+c
okay..divide -8 by 2
So, it would be -4².. And c would equal 16. So the equation would be x²-8x+16?
YEP!!
Yay! Okay, so do you divide by 2 every single time?
not everytime...
just when you're finding the c
for example you are given x^2 + bx + 25 and find b
do you know how you can get it?
No..
okay...review!! x^2 + 10x + c how will you find c??
You divide by 2.
then..?
Square the quotient.
so you divide the middle term by 2..then square it...the result is the third term so if you're given x^2 + bx + 25 this is reverse... get the square root of 25..that gives you 5 then multiply it by 2!! yay let me give you a formula the general form is \(ax^2 + bx + c\) when c is missing \[(\frac{b}{2})^2 = c\] when b is missing \[\sqrt{2c}\] got it?
uhmm woops sorry \[b = 2\sqrt c\]
I don't have to deal with b though.. all the ones on my worksheet are with x's after the first 3.
Like, the next one says: Write each trinomial as a perfect square: x²+4x+4
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