Question

Plz help:)

Answer 1

Please solve according to above attachment:)
this one: -\[\sqrt{i}.\]

Answer 2

What exactly is ur question? i cant see what you typed kinda unclear. is it a sqrt(i)?

Answer 3

ya it is: -

Answer 4

@tiaph

Answer 5

Let sqrt(i) = x+yi

squaring both sides,

i = x^2 - y^2 + 2xyi

By equating the real parts and the un real parts,
x^2 - y^2 = 0 and 2xy=1

x^2-y^2 = 0
x^2= y^2
x=y

Substitute x=y to 2xy=1

2x^2 = 1
x^2 = 1/2
x= sqrt(1/2)

Since x= sqrt(1/2), y also =sqrt(1/2)

sqrt(i) = x+yi
= sqrt(1/2) + sqrt(1/2) i

Answer 6

@tiaph why it is not like this:?\[\sqrt{1/2}=\pm 1/\sqrt{2}.\]

Answer 7

yea that is also the same.

Answer 8

then why did u put only x= 1/sqrt{2} in ur solution?

Answer 9

can't we write this as