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Chemistry 7 Online
OpenStudy (anonymous):

a 45 kg of lead is heated from 11 degrees to 125 degrees C. how much heat was required during the heating? pleasee help, last question and i dnt get it.

OpenStudy (anonymous):

45kg*1000g=45000g. Q=45000g*0.128J/g-C*114C So, Ans is Q=656640J or 656.64kJ. I think it should be 2 sigfig Q is heat =Mass in gram*heat capacity*change in temp Temp final-temp initial

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