Question

Find the equation in standard form which passes through (3, –6) and (–2, –1). You must show all work.
I am so stuck... :(

Answer 1

First lets find the slope. You know how?

Answer 2

y2 - y1/x2 - x1??

Answer 3

yes..

Answer 4

so whats the slope

Answer 5

5/-5

Answer 6

great..thats -1

Answer 7

so do you know the eqn of a line...

slope = (y-y1)/(x-x1) ??

Answer 8

?

Answer 9

I plug it into that now?

Answer 10

yes

Answer 11

is it just y - -6 for the top?

Answer 12

precisely

Answer 13

Ah, i'm confused

Answer 14

why?

Answer 15

(y - - 6) / (x-3) = -1

wts wrong?

Answer 16

didn't we just do that?

Answer 17

thats all
simplify that
(y+6)/(x-3) = -1
so

y+6 = 3-x

Answer 18

it should be y - y1 = m(x - x1)

Answer 19

same thing

Answer 20

isnt it

(y- - 6) = -1(x-3)?

Answer 21

?

Answer 22

i figured it out

Answer 23

so the answer is?

Answer 24

y = -x + 6

Answer 25

no

Answer 26

-1 + 6 which is 5 so y = 5

Answer 27

y + 6 = 3 - x
x+y + 3 =0

Answer 28

isnt it?

Answer 29

I don't know, i just typed in what i just said... I'm just stuck on this other one now

Answer 30

ok..lets see that