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OpenStudy (anonymous):
draw a graph that represents the solution to the given system? 1. y = –x + 2
y = 3x – 1
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OpenStudy (anonymous):
It turns out so ugly :D
OpenStudy (anonymous):
Just draw the graphs for both equations on same coordinates and find the solution at the intersection of the two lines
OpenStudy (anonymous):
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OpenStudy (anonymous):
thankyou soo much :)
OpenStudy (anonymous):
draw a graph that represents the solution to the given system?
can you help with this one
–4x + 3y = –12
–2x + 3y = –18
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OpenStudy (anonymous):
First, write it as y = mx + b
OpenStudy (anonymous):
Can you do that?
OpenStudy (anonymous):
ya i think so
OpenStudy (anonymous):
now what
OpenStudy (anonymous):
do you graph it or put y on both sides haha i kinda forgot it its been awhile
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OpenStudy (anonymous):
You have y alone on one side and should be able to easily "see" the graph. m is the slope and b is where the line will start..
OpenStudy (anonymous):
im sorry i still dont understand
OpenStudy (anonymous):
|dw:1339007008950:dw|
OpenStudy (anonymous):
m is the slope. Which means when you move one unit on the x-axis, you will move m units on the y-axis
OpenStudy (anonymous):
b is where on the y-axis the line starts
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OpenStudy (anonymous):
|dw:1339007173069:dw|
OpenStudy (anonymous):
in this case, m = 2, where you move twice for each on the x-axis
OpenStudy (anonymous):
–4x + 3y = –12 => 3y =-12+4x => y = 4/3x-4
–2x + 3y = –18 => 3y = -18+2x => y = 2/3x+6
OpenStudy (anonymous):
i get it now thankyou soo much for taking the time to help me now i can do the rest on my own :)
OpenStudy (anonymous):
Glad I could help :b
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