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Derive y = lnx / (x^1/6)
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find Derivative ?
yes
u=lnx =>du=1/x dv=x^(1/6) =>v=6/5x^(5/6) \[\int\limits_{}^{}=u*v-\int\limits_{}^{}vdu\]
sorry
you can write it as \(\huge y=(x^{-\frac{1}{6}})\times lnx \) and use the product rule.... much simpler...
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I confusion antiderivative
(uv)'=u'v+uv'
\(\large y'=[x^{-\frac{1}{6}}]'lnx+[lnx]' x^{-\frac{1}{6}} \)
can that be simplified any further?
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