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Mathematics 16 Online
OpenStudy (anonymous):

For binomial distribution: E[X] = n(pi) and variance is n(pi)(1-pi). How do i prove variance?

OpenStudy (zarkon):

really the same technique as deriving the the mean

OpenStudy (zarkon):

compute \[\mathbf{E} [X(X-1)]\]

OpenStudy (anonymous):

E[X^2 - X] = E[X^2] - E[X?]

OpenStudy (anonymous):

and then expand from there?

OpenStudy (zarkon):

compute it using the pdf of the binomial

OpenStudy (zarkon):

of pmf if you prefer that notation

OpenStudy (anonymous):

Ok. Thank you very much. I shall keep that in mind in todays exam

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