Question

These are Quadratic Equations. and the question asks us to solve the equation by finding the square roots. 3x squared = 15. that is all i understand.

Answer 1

first step divide both sides by 3

Answer 2

what do you get?

Answer 3

1 and 5

Answer 4

\[x^2 = 5\] now to get rid of the square in x just take square root of both sides \[\sqrt x^2 = \sqrt 5\] \[x = \sqrt 5\]

Answer 5

do you get that?

Answer 6

Yes! That was not as hard as I thought! Thank you very much!

Answer 7

happy to help ^_^

Answer 8

OK not another one. 36x squared = 256. so i divide each side by 36?

Answer 9

yup

Answer 10

note...dont put it in decimal form ;) if you dont get a whole number when you divide but put as fraction

Answer 11

just put as fraction*

Answer 12

1/7

Answer 13

i dont thing 256/36 = 1/7

Answer 14

i dont think*

Answer 15

let me just show you how to do it \[36x^2 = 256\] \[x^2 = \frac{256}{36}\] both 256 and 36 are perfect squares so if i square root both sides... \[\sqrt x^2 = \sqrt{\frac{256}{36}}\] \[x = \frac{16}{6}\] 16 is the square root of 256 and 6 is the square root of 36

Answer 16

OK thanks! This math is new to me!

Answer 17

haha..it's cool :)) well manipulating it is cool lol