Question

A ball is dropped from a height of 20.0m. It falls for 2.00 seconds. It's velocity is 24.6 m/s when it hits the ground. Find the acceleration of the ball when it hits the floor.

Answer 1

Use the two kinematic equations, \[y=y _{0} +v_{0_{y}} t+(1/2)at ^{2}\] and \[v _{y} = v_{0_{y}} + a_{y}t\]. With the second equation, solve for v_0:\[v _{0} = v_{y} - at\]. Then substitute for v_0 and solve for a.

Answer 2

variable acceleration?!

Answer 3

Uint=initial velocity, V= to the given velocity, a=acc, h=height