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In calculus, how do you find the normal line equation when given the tangent line equation
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normal line means perpendicular line
^does that help?
normal line = \[-1/ f'(a) \]
When you have a line in point-slope form,\[y-y_0=m(x-x_0)\]the unique line perpendicular to it is given as follows.\[y-y_0=-\frac{1}{m}(x-x_0)\]This is jus more of a line geometry problem than a calculus problem.
@yakeyglee You actually have this in calculus.
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Thank you all :D
No problem.
@beeqay - What I meant was that it wasn't a calculus technique.
the normal line is the one that isn't abnormal...:)
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