how to differentiate this?
\[h= 22t-4.9t^{2}\]
@apoorvk
power rule
22t involves the constant multiple rule where in derivative of ax where a is a constant is equal to a
as for -4.9t^2 use power rule \[ax^n = nax^{n-1}\]
get it @thushananth01 ??
Remember these rules when differentiating functions like these 1) When differentiating a constant, f'(x) = 0 2) When differentiating a exponential r*x^(r-1) ** r is the power for example x^2, differentiates to 2x, or 2x^2 differentiates to 4x 3) when different a constant times a variable, the differentiation is the constant for example 6x becomes 6, 2x becomes 2 Although the formal definition is defined as \[\lim_{x \rightarrow h} f(x + h) - f(x) / h\]
\[1.\frac{dx^n}{dx} = nx^{n-1}\] \[2.\frac{d(ky)}{dx} = \frac{k.d(y)}{dx}\] \[3. \frac{d(u \pm v)}{dx} = \frac{d(u)}{dx} \pm \frac{d(v)}{dx}\]
oh...okay so...what si the answer
Use these three^
@thushananth01 if you want you can check this out http://openstudy.com/study#/updates/4f9cb59de4b000ae9ed1a3e8 for an awesome tutorial on differentiation
i did i am getting \[-9.8t-22\]
o.O??????????
close..no negative for 22
it's simply 22 - 9.8t got it?
why no negative for -22?
22t...<--derivative of that is just take away t
oh okay
but then the answers is \[22- 9.8t\] right
yes it is
thansk alot..bro
sure thing ^_^
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