Question

with α = dω / dt what does d stand for? thx :)

Answer 1

it's a derivative

so in this case, alpha is equal to the change in omega with respect to time

Answer 2

\[α =\frac{\text dω }{\text dt}=\frac{\text d^2\theta }{\text dt^2}\]
\[α=\omega^\prime=\theta''\]
\[\alpha=\dot\omega=\ddot\theta\]

Answer 3

Does that mean that α = dω / dt gives you the average angular acceleration then?

Answer 4

so whats the formual for just the angular acceleration is it α = ω / t

Answer 5

no, \(\frac{\text d(~~)}{\text dt}\) mean you take the derivative
of what is inside the brackets with respect to time

Answer 6

But when you take the derivative of something say y=3x + x^2 the derivative of Y with respect to x = 3+2x right? so if ω= say just a number then how can you take the derivative of it?

Answer 7

\(\omega\) is not just a number, omega will have units of either

\(\left[\frac{\text{ radiens}}{second}\right] \) or\(\left[\frac{\text{degrees}}{\text{second}}\right]\)

\(\omega\) will be a function of time \(\omega(t)\) instead of \(y(x) \)

Answer 8

@Missfranglish
Quote : "Does that mean that α = dω / dt gives you the average angular acceleration then?"

Answer: No it doesn't!

α = dω / dt gives you intantaneous angular acceleration
α = ω / t gives you average angular acceleration