Say that a and b are the lengths of the legs of a right triangle and c is the length of the hypotenuse. Find b if a = 21 and c = 29. A) b =40 B) B = 20 C) B= 10 D) B = 400
Pythagorean *whistles* You're welcome
\( \color{Black}{\Rightarrow 21^2 + x^2 = 29^2 }\)
21²= 441
Correct?
\( \color{Black}{\Rightarrow x^2 = 29^2 - 21^2 }\) \( \color{Black}{\Rightarrow x^2 = 841 - 441 }\) \( \color{Black}{\Rightarrow x^2 = 400 }\) \( \color{Black}{\Rightarrow x = \sqrt{400} = ...? }\)
So it would be 25²+400=29²
29²=841
How did you get that 25 :/
typo.. I meant 21²
Exactly
\( \color{Black}{\Rightarrow x^2 = 841 - 441 = 400 }\)
Wow, thanks, that helped alot.
\( \color{Black}{\Rightarrow x = \sqrt{400} }\)
its b 20cm
@harshendu_pandey maybe you would like to explain your answer :)
don't answer for them... it's open STUDy not openAnswers... :P
@Ruhhr
from pythagoras theorum c2=a2+b2 b2=c2-a2 b2=(29)2-(21)2 b2=841-441 b2=400 b=20
Good, but I had already explained the same :P
Wait I don't understand how it's 20 when I got 400
What is square root of 400?
b2 is 400... you still need to take the quare root to get b...
\( \color{Black}{\Rightarrow x \times x = 400 }\) There's one number that when is multiplied to itself, gets you 400. That number is 20 :D
There are actually two solutions. -20 or 20, but a side of a triangle can't be in negative :)
So there is only one solution to this answer.
Oh, alright, got it!
Hah! nice!
Join our real-time social learning platform and learn together with your friends!