Mathematics
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OpenStudy (anonymous):
if 2^x = 15^y = 3^z = 10^w yhen 1/x + 1/y :1/z+ 1/w is?
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OpenStudy (experimentx):
not sure this will work
let,
2^x = 15^y = 3^z = 10^w = k
x = k/ln2
OpenStudy (experimentx):
sorry, lnk/ln2
OpenStudy (experimentx):
Oops ... we can express it interms of z
OpenStudy (anonymous):
@experimentX u r 1st way is correct plzz go on
OpenStudy (experimentx):
\[ \frac{\ln 2+\ln 15 + \ln 10}{\ln k} = \frac{\ln 300}{\ln k}\]
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OpenStudy (anonymous):
wat is in
OpenStudy (experimentx):
I think we have to replace k with z
OpenStudy (anonymous):
ok then
OpenStudy (experimentx):
\ln k = z \ln 3
i guess
\[ \frac{\ln 300}{z\ln3}\]
OpenStudy (anonymous):
@experimentX any other way!
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OpenStudy (experimentx):
lol ... i'm not quite good with algebra ... if you know the answer, i might able to connect it.
OpenStudy (anonymous):
sorry for the mistake in question plz look the question now
OpenStudy (anonymous):
if 2^x = 15^y = 3^z = 10^w yhen 1/x + 1/y :1/z+ 1/w is?
OpenStudy (experimentx):
Oh ... sorry,
i didn't see the : in the question
OpenStudy (anonymous):
@experimentX it was not there i just edited now
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OpenStudy (experimentx):
use same approach ... cancel out ln k
OpenStudy (anonymous):
sorry for the mistake
OpenStudy (experimentx):
\[ \frac{\ln 30}{\ln 300}\]
OpenStudy (anonymous):
The answer should be 1:1 @experimentX
OpenStudy (experimentx):
OH ... let's see where i made mistake
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OpenStudy (experimentx):
Oh .. sorry again, i thought that 3 was 30
OpenStudy (anonymous):
i did nt understand those things plz do in other way
OpenStudy (anonymous):
@FoolForMath
OpenStudy (experimentx):
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