Mathematics
8 Online
OpenStudy (anonymous):
if 5^x + 4^y = 3189 and 5^(x-3) + 4^(y+1) =281 then x-y= ?
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OpenStudy (apoorvk):
take natural log of both sides!
for the second one, simplify it a bit before taking log.
OpenStudy (mathmagician):
x-y=2
OpenStudy (lgbasallote):
@lgbasallote
OpenStudy (anonymous):
@Yahoo! , @apoorvk is correct, its a bit like that last question i helped you with
OpenStudy (experimentx):
try to find the value of 5^x and 4^y first ... not sure though..
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OpenStudy (anonymous):
the answer is 2
OpenStudy (experimentx):
let 5^x = a and 4^y=b
OpenStudy (anonymous):
ok
OpenStudy (experimentx):
though there might be some other better method ..
OpenStudy (anonymous):
No @experimentX plz continue let see wat u get plz
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OpenStudy (experimentx):
a + b = 3189
a/125 + 4 = 281
OpenStudy (anonymous):
i am wondering what the snap way to do this is
i get
\[a+b=3189, \frac{1}{125}a+4b=281\]
OpenStudy (anonymous):
but since you are looking only for \(x-y\) maybe there is an easier way
OpenStudy (anonymous):
i got b=64 a=3125
OpenStudy (anonymous):
but i think this does not help
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OpenStudy (phi):
it helps a lot
OpenStudy (anonymous):
ok so \(4^y=64\implies y=3\) right?
OpenStudy (experimentx):
still there must be some algebraic trick ... if somebody gets it .. let me know first
OpenStudy (anonymous):
similarly \(5^x=3125\implies ...\)
OpenStudy (anonymous):
maybe this is the best way. i cannot think of a snap one
notice it does not use logs
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OpenStudy (anonymous):
6
OpenStudy (phi):
5^5= 3125
OpenStudy (anonymous):
actually \(5^5=3125\) and \(5-3=2\)
OpenStudy (anonymous):
sorry
OpenStudy (anonymous):
thxxxx @phi @satellite73 @experimentX
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OpenStudy (experimentx):
yw