HELP PLEASEE :
Solve: x2 – 36 = 0 and x2 = 8x – 12 and show your work.
Describe what the solution(s) represent to the graph of each.
How are the graphs alike? How are they different?

Question

HELP PLEASEE : 
Solve: x2 – 36 = 0 and x2 = 8x – 12 and show your work. 
Describe what the solution(s) represent to the graph of each.
How are the graphs alike? How are they different?

anonymous · Answer

Ok, lets see what you have.

anonymous · Answer

The first equation is what we call a special case quadratic. The reason is that it has the form: $$a^2-b^2=(a+b)(a-b)$$
Where a is x and b is 6, i.e:
$$x^2-36=(x)^2-(6)^2=(x+6)(x-6)$$

anonymous · Answer

So if $$(x+6)(x-6) = 0$$, the only way for this to be true is if x equals -6 or +6