Question

HELP PLEASEE :
Solve: x2 – 36 = 0 and x2 = 8x – 12 and show your work.
Describe what the solution(s) represent to the graph of each.
How are the graphs alike? How are they different?

Answer 1

Ok, lets see what you have.

Answer 2

The first equation is what we call a special case quadratic. The reason is that it has the form: \[a^2-b^2=(a+b)(a-b)\]
Where a is x and b is 6, i.e:
\[x^2-36=(x)^2-(6)^2=(x+6)(x-6)\]

Answer 3

So if \[(x+6)(x-6) = 0\], the only way for this to be true is if x equals -6 or +6