Find the geometric means in the following sequence 30,?,?,?,?,-3900000
is that \(-3,900,000\) at then end or \(390,000\) ?
-3900000
\[30, 30r,30r^2,30r^3,30r^4,30r^5=-3,900,000\] \[\frac{-3,900,000}{30}=r^5\] \[r^5=-130,000\] \[r=\sqrt[5]{-130,000}\]
looks kind of ugly, did i write something incorrectly?
maybe i am completely wrong.
Looks right to me. the common ratio is between -11 and -10.
\[r=-10^{\frac{4}{5}}\sqrt[5]{13}\]hmmm
So it would be 390,3900,39000,390000
Does the answer need to be a simplified expression of an exact value or will a decimal approximation do?
Am I right?
Are you sure? Definition is: \[\text{If } (x_1,\dots,x_n) \text{ then } G=\left(x_1\cdots x_n\right)^{\frac{1}{n}}\]
good point @Limitless
Wiki: "For instance, the geometric mean of two numbers, say 2 and 8, is just the square root of their product; that is 2√2 × 8 = 4. As another example, the geometric mean of the three numbers 4, 1, and 1/32 is the cube root of their product (1/8), which is 1/2; that is 3√4 × 1 × 1/32 = ½."
i wrote the common ratio, not the geometric mean
I don't know what the ?'s are in: 30,?,?,?,?,-3900000 The GM is not defined unless we know them...
If the common ratio is \[\sqrt[5]{\frac{-3900000}{30}}\] Then the terms are (approximately) 30, -316.16, 3331.95, -35114.56, 370063.23, -3900000
I think by "Find the geometric means," it means to find the missing terms.
i was assuming it was a geometric sequence, \[\{a,ar, ar^2, ar^3, ar^4, ar^5\}\] but i could be wrong in which case you would have geometric mean as \[\sqrt[6]{a^6r^{15}}=a\sqrt[3]{r^5}\]
OP needs to clarify. We can conjecture a lot and get nowhere. :P
this looks messy too, but who knows
I think Satellite has it: \[GM=30x^{5/3}, x=\sqrt[5]{\frac{-3900000}{30}}\] \[\rightarrow 30\sqrt[3]{-130000}\]
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