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Mathematics 12 Online
OpenStudy (anonymous):

Trigonometry question see pic in comments

OpenStudy (anonymous):

OpenStudy (anonymous):

if you cant read it The diagram s show a sector of radius 10cm and angle @ radians which is formed into a cone slant height of 10 cm. the verticle height h of the cone is equal to the radius r of its base. Find the angle @ radians

OpenStudy (phi):

Do you know how to find the surface area of the cone? It (not counting its bottom) must match the area of the part of the circle used to make the cone.

OpenStudy (anonymous):

no, can you explain?

OpenStudy (phi):

try google to find the surface area of a cone, and post the formula

OpenStudy (anonymous):

\[\pi rs +\pi r ^{2}\]

OpenStudy (phi):

the second part is the bottom of the cone. It does not count. The first term pi * r *s is the part formed by the circle. you know s (the slant height) see your picture. you know height of the cone equals the radius, so you can figure out what r is (45-45-90 triangle)

OpenStudy (anonymous):

yes i found the surface area as 379 cm^2

OpenStudy (phi):

the area of the circle is pi r^2 = 100 pi now find the fraction theta/2*pi that matches the cone.

OpenStudy (anonymous):

as in theta/2pi = 100 pi ?

OpenStudy (phi):

no. as in \[ 100 \pi \frac{\theta}{2 \pi} = \text{area of cone} \]

OpenStudy (phi):

btw, double check your answer for the area of the cone's top surface. I got 222.14

OpenStudy (anonymous):

πrs+πr2, isnt that the formula for surface area of a cone? πrs = 222.14

OpenStudy (phi):

yes, but the pi r^2 is not part of the circle. It is the bottom of the cone, which is open in this case. Look at the picture, or go fold a piece of paper to get an idea of what is happening.

OpenStudy (anonymous):

oh right, thanks :)

OpenStudy (phi):

btw, lots of times people would leave the answer as \[ \theta= \sqrt{2} \pi \] rather than theta = 4.443 (rounded)

OpenStudy (anonymous):

how did you get that answer? It is right but I dont understand the last steps

OpenStudy (phi):

First, what is the area of the cone without simplifying to a single number.

OpenStudy (anonymous):

222.11

OpenStudy (phi):

no, pi *r*s with out simplifying

OpenStudy (anonymous):

pi 7.07 x 10

OpenStudy (phi):

what is 7.07 before you simplify?

OpenStudy (anonymous):

oh ok, sq root 50

OpenStudy (anonymous):

\[\pi \sqrt{50} \times 10\]

OpenStudy (phi):

now we can simplify it this way 50= 25*2 so sqrt(50)= sqrt(25)*sqrt(2)= 5*sqrt(2) we get \[ \pi 50 \sqrt{2} \] that is an exact result (remember 7.07 is only approximately sqrt(50)) now we solve the equation \[ 100 \pi \frac{\theta}{2 \pi} = \pi 50 \sqrt{2} \]

OpenStudy (phi):

the left hand side is the area of the circle (pi r^2 with r=10) but we only want a fraction of the whole area. 2 pi is the whole way round theta is part way round. theta/2pi is a fraction of the circle...does that make sense?

OpenStudy (anonymous):

Yes thank you so much, I get it now :D

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